博文
Mathematica画曲线的交线
|||
ContourPlot3D[{z == x y, x^2 + y^2 == 1}, {x, -2, 2}, {y, -2,
2}, {z, -2, 2}, Mesh -> None, Axes -> None,
BoundaryStyle -> {1 -> None, 2 -> None, {1, 2} -> {Red, Tube[.05]}},
Boxed -> False, Axes -> None]
ContourPlot3D[{z==x^2+y^2,zŠ4-x^2-y^2},{x,-2,2},{y,-2,2},{z,-4,4},Mesh®None,BoundaryStyle®{1->None,2®None,{1,2}®{Red,Tube[.05]}},Boxed®False,Axes®None]
参考：http://www.math.org.cn/forum.php?mod=viewthread&tid=26728&extra=page%3D1
https://blog.sciencenet.cn/blog-287000-680257.html
上一篇：2013年04月15日科目一练习
下一篇：2012最新分区2012中科院数学SCI分区
