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怎么将对称蛋白沿某个方向摆正

已有 2003 次阅读 2018-7-16 16:24 |个人分类:分子模拟|系统分类:科研笔记| 蛋白质, 旋转, 垂直, 对称

Using VMD to rotate the protein so as to it's vertical to z axis.

you need to get the v by vector.sh.

vector.sed must be prepared for calling.

the symmstry here is four monomers, however three points define one surface.

the resid need to reconfigure in vector.sed to get the v.

其中vector.sh:

#!/bin/sh bash
#used to give out the vector of your protein.
#for the purpose that an equilibrium will be got more quickily
#you can get the vector vetical to dirction of the membrane plane.
#if you want to change the residue for calculating,please open vector.sed and change it correspondently.
 
sed '1d;2d;$d' start.gro >temp1
sed -f vector.sed temp1 1>log
paste aa1 aa2 aa3 aa4>temp2
# x1,x2,x3
awk '{print (($11-$5)*($18-$6)-($17-$5)*($12-$6))/(($10-$4)*($17-$5)-($11-$5)*($16-$4)),(($10-$4)*($18-$6)-($16-$4)*($12-$6))/(($11-$5)*($16-$4)-($10-$4)*($17-$5)),1}' temp2 >temp3
# x2,x3,x4
awk '{print (($17-$11)*($24-$12)/($23-$11)-($18-$12))/(($16-$10)-($17-$11)*($22-$10)/($23-$11)),(($16-$10)*($24-$12)-($22-$10)*($18-$12))/(($17-$11)*($22-$10)-($16-$10)*($23-$11)),1}' temp2 >>temp3
# x3 x4 x1
awk '{print (($23-$17)*($6-$18)-($5-$17)*($24-$18))/(($22-$16)*($5-$17)-($23-$17)*($4-$16)),(($22-$16)*($6-$18)-($4-$16)*($24-$18))/(($23-$17)*($4-$16)-($22-$16)*($5-$17)),1}' temp2 >>temp3
# x4 x1 x2
awk '{print (($5-$23)*($12-$24)-($11-$23)*($6-$24))/(($4-$22)*($11-$23)-($5-$23)*($10-$22)),(($4-$22)*($12-$24)-($10-$22)*($6-$24))/(($5-$23)*($10-$22)-($4-$22)*($11-$23)),1}' temp2 >>temp3
awk 'BEGIN {aver_x=aver_y=aver_z=0;n=0} {aver_x+=$1;aver_y+=$2;aver_z+=$3;n++} END {print aver_x/n,aver_y/n,aver_z/n}' temp3
rm temp1
rm temp2
rm temp3
rm aa[1234]

vector.sed为:

#work with vector.sh
1,1469w aa1
1470,2938w aa2
2939,4407w aa3
4408,$w aa4\0

得到方向矢量之后,在vmd里进行旋转:

set all [atomselect top all]

$all move [transvecinv v]  #v={x y z}

视情况,再进行$all move [transaxis x 90]

最后$all writepdb "new.pdb"



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