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转贴一篇文章,来自英国《泰晤士报·高等教育专刊》,名为
想请教一下专家:"self-plagiarism"(在仅做少量修改的情况下,重复发表自己以前的研究成果)是翻译成“自我剽窃”呢还是别的什么?
此文要点是:
文章摘要(全文链接附后):
Pressure to publish is pushing many academics to plagiarise large volumes of their own work by "dressing up" their old research to appear as if it were new, a study has found.
Researchers using text-matching software have highlighted the phenomenon of "self-plagiarism", in which academics recycle sections of their previously published work without proper citations.
Scholars who engage in the practice, which undermines academia's pursuit of original knowledge, can gain an unfair career advantage over their more honest colleagues, the researchers say.
A pilot study by Tracey Bretag and Saadia Carapiet from the University of South Australia found that 60 per cent of authors in a random sample of 269 papers from the Web of Science social science and humanities database had self-plagiarised at least once in the period 2003-06. Self-plagiarism was defined "quite generously" as occurring when 10 per cent or more text from any single previous publication was reused without a citation.
This month sees the launch of CrossCheck, an anti-plagiarism system for academic journals created by iParadigms to help publishers verify the originality of submitted work. It will cover 20 million journal articles from major publishers including Elsevier, Nature Publishing Group, Oxford University Press and Sage.
Liz Smith, the head of journal development at Elsevier, said: "Self-plagiarism does happen - it actually happens frequently, I think. We see redundant publication, when the same data are given a different slant, and we've had to withdraw papers that have turned out to be duplicates or near duplicates."
CrossCheck will help editors to spot many types of ethical infringement, she said. "It doesn't matter whether you are duplicating someone else's text or your own, if it is in the CrossCheck database, or on the web, it will be picked up."
http://www.timeshighereducation.co.uk/story.asp?sectioncode=26&storycode=402598&c=2
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