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题记:
1) 脚本的撰写者对DOSCAR文件的格式及计算流程有很深的了解;
2) 感谢撰写者的辛勤劳动及无私奉献
3) 当然,该脚本要达到普适,仍需修改很多地方
program read_dos
integer nlines,natoms,i,j,nepsi,natoms1
character(len=80) :: f(100),f0
real*4 emin,emax,nume,Ef,a
real*4 E1(5000),E2(5000),E4(5000),dos(5000),intdos(5000),dos_s(5000,5000),dos_pn1(5000,5000),dos_p0(5000,5000),dos_pp1(5000,5000),E(5000,5000),E3(5000,5000)
real*4 dos_dn2(5000,5000),dos_dn1(5000,5000),dos_d0(5000,5000),dos_dp1(5000,5000),dos_dp2(5000,5000)
real*4 dos_p(5000,5000),dos_d(5000,5000),delta
real*4 intedos_ds1,intedos_dp1,intedos_dd1,intedos_ds2,intedos_dp2,intedos_dd2,intedos_all
real*4 dos_s_total_2(5000),dos_p_total_2(5000),dos_d_total_2(5000),dos_s_total_1(5000),dos_p_total_1(5000),dos_d_total_1(5000)
character(len=6) int_to_char
open(100,file='DOSCAR')
open(200,file='dos_total.dat')
open(300,file='dos_total_1.dat')
open(400,file='dos_total_2.dat')
f0='_dos.dat'
write(*,*) "please input the Ef"
read(*,*)Ef
write(*,*) "please input the number of atoms in the POSCAR file"
read(*,*)natoms
write(*,*) "please input the number of the first atoms in the POSCAR file"
read(*,*)natoms1
do i=10,natoms+9
f(i)=trim(int_to_char(i))//trim(f0)
open(i,file=trim(f(i)))
enddo
read(100,*)
read(100,*)
read(100,*)
read(100,*)
read(100,*) #跳过DOSCAR文件前面5行,从第6行开始起读
read(100,*) emax,emin,neps,Ef,a
delta=0.0
delta=(emax-emin)/1000
intedos_all=0.0
do i=1,neps
read(100,*)E1(i),dos(i),intdos(i) #第7行数据
E2(i)=E1(i)-Ef
intedos_all=intedos_all+dos(i)*delta
write(200,10)E2(i),dos(i),intdos(i),intedos_all #这两个数值有细微差别
enddo
do i=10,natoms+9
read(100,*) #空一行 即从1008行开始读取数据
do j=1,neps
read(100,*)E(i,j),dos_s(i,j),dos_p(i,j),dos_d(i,j)
E3(i,j)=E(i,j)-Ef #减去费米能级的修正
write(i,10)E3(i,j),dos_s(i,j),dos_p(i,j),dos_d(i,j)
enddo
enddo
dos_s_total_1(j)=0.0
dos_p_total_1(j)=0.0
dos_d_total_1(j)=0.0
dos_s_total_2(j)=0.0
dos_p_total_2(j)=0.0
dos_d_total_2(j)=0.0
intedos_ds1=0.0
intedos_dp1=0.0
intedos_dd1=0.0
intedos_ds2=0.0
intedos_dp2=0.0
intedos_dd2=0.0
do j=1,neps
do i=10,natoms1+9
dos_s_total_1(j)=dos_s_total_1(j)+dos_s(i,j)
dos_p_total_1(j)=dos_p_total_1(j)+dos_p(i,j)
dos_d_total_1(j)=dos_d_total_1(j)+dos_d(i,j)
E4(j)=E3(i,j)
intedos_ds1=intedos_ds1+dos_s_total_1(j)*delta
intedos_dp1=intedos_dp1+dos_p_total_1(j)*delta
intedos_dd1=intedos_dd1+dos_d_total_1(j)*delta
enddo
write(300,20)E4(j),dos_s_total_1(j),dos_p_total_1(j),dos_d_total_1(j),intedos_ds1,intedos_dp1,intedos_dd1 #intedos_dp1 怎么会大于总的态密度积分值呢? 费解!!!
enddo
do j=1,neps
do i=natoms1+10,natoms+9
dos_s_total_2(j)=dos_s_total_2(j)+dos_s(i,j)
dos_p_total_2(j)=dos_p_total_2(j)+dos_p(i,j)
dos_d_total_2(j)=dos_d_total_2(j)+dos_d(i,j)
E4(j)=E3(i,j)
intedos_ds2=intedos_ds2+dos_s_total_2(j)*delta
intedos_dp2=intedos_dp2+dos_p_total_2(j)*delta
intedos_dd2=intedos_dd2+dos_d_total_2(j)*delta
enddo
write(400,20)E4(j),dos_s_total_2(j),dos_p_total_2(j),dos_d_total_2(j),intedos_ds2,intedos_dp2,intedos_dd2
enddo
10 format(1x,f8.4,1x,f8.4,1x,f8.4,1x,f8.4)
20 format(1x,f8.4,1x,f8.4,1x,f8.4,1x,f8.4,1x,f8.4,1x,f8.4,1x,f8.4)
end
!-----------------------------------------------------------------------
FUNCTION int_to_char( int )
!-----------------------------------------------------------------------
IMPLICIT NONE
INTEGER, INTENT(IN) :: int
CHARACTER (LEN=6) :: int_to_char
IF ( int < 10 ) THEN
WRITE( UNIT = int_to_char , FMT = "(I1)" ) int
ELSE IF ( int < 100 ) THEN
WRITE( UNIT = int_to_char , FMT = "(I2)" ) int
ELSE IF ( int < 1000 ) THEN
WRITE( UNIT = int_to_char , FMT = "(I3)" ) int
ELSE IF ( int < 10000 ) THEN
WRITE( UNIT = int_to_char , FMT = "(I4)" ) int
ELSE
WRITE( UNIT = int_to_char , FMT = "(I5)" ) int
END IF
RETURN
END FUNCTION int_to_char
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