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在EXCEL中用Newton迭代法求解x^3-27=0的根
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初值为x0 = 1;
f(x) = x^3-27
f'(x)=3x^2
x_{k+1}=x_k-f(x_k)/f'(x_k),k=0,1,2,\cdots.
https://blog.sciencenet.cn/blog-292361-1086117.html
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初值为x0 = 1;
f(x) = x^3-27
f'(x)=3x^2
x_{k+1}=x_k-f(x_k)/f'(x_k),k=0,1,2,\cdots.
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