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历史的数学线索：裸奔＝宠幸－1
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历史的数学线索：裸奔＝宠幸－1
裸奔是一个新的网络词汇，其含义绝对不是裸体跑步。
如果裸奔是裸体跑步，那鉴定裸奔就太容易了。
GOOGLE: 科学网：裸奔
裸奔应该是一种境界，什么境界呢？
还是先从宠幸一词说起吧。
宠幸是描述皇帝下部生活的专有名词。
如果皇帝绝对地、压倒一切地、无条件地搞了一个女人，太监们则会说，皇帝宠幸了这个女人。
由此可见，宠幸不仅仅指皇帝和女人的身体动作，更多的是指皇帝和女人的精神和灵魂层次的动作。
被皇帝宠幸之后，无论那女人是笑还是哭，是偷笑还是偷哭，都被太监们认为是一种至高无上的幸福。
由此可见，宠幸并不是男女之间的意思，而是皇帝搞女人的意思，是一种1 VS N的关系。
皇帝可以强奸任何人，强奸之后给她（他）追认一个名号，因此，强奸的动作就被追认为宠幸了。
裸奔和宠幸有什么关系呢？
裸奔和宠幸没有关系，但是，裸奔和宠幸的逆（矩阵）有一定关系。
A是一个矩阵，如果有逆矩阵A-1的话，则AA-1=I。
这就是儒家“天人合一”的数学表述。
因此，宠幸×裸奔=I。
再说说裸奔。
如果裸奔是裸体跑步（奔跑），那实现裸奔也太容易了。
自然界别的动物都没有穿衣服，那动物世界不就成了一个裸奔的世界了吗？
俗话说，“大鹏一展翅，能飞九万里”，一般指大鹏鸟“穿”着羽毛飞翔。
把大鹏鸟的羽毛褪去，如果大鹏鸟还能飞翔，这就是名副其实的裸飞。
裸飞容易吗？
不容易，裸飞太难了。
裸奔容易吗？
裸奔也不容易，能做到裸奔真是太难了。
附录：没有排列组合就没有优化组合
（选自俺自己的《坐标变换和函数变换》）
D3（C3v）群的“排列组合”表示。
如果取一组6维基矢量，“横向”有48种满足正交条件的排列，3组（符号排列不同）的基矢量，有3×48＝144种。
基矢量排列：
'Row 1
MA(nX, kk(1), 1) = 1 / Sqr(6)
MA(nX, kk(1), 2) = 1 / Sqr(6)
MA(nX, kk(1), 3) = 1 / Sqr(6)
MA(nX, kk(1), 4) = 1 / Sqr(6)
MA(nX, kk(1), 5) = 1 / Sqr(6)
MA(nX, kk(1), 6) = 1 / Sqr(6)
'Row 2
MA(nX, kk(2), 1) = 1 / Sqr(6)
MA(nX, kk(2), 2) = 1 / Sqr(6)
MA(nX, kk(2), 3) = 1 / Sqr(6)
MA(nX, kk(2), 4) = -1 / Sqr(6)
MA(nX, kk(2), 5) = -1 / Sqr(6)
MA(nX, kk(2), 6) = -1 / Sqr(6)
'Row 3
MA(nX, kk(3), 1) = 2 / Sqr(12)
MA(nX, kk(3), 2) = -1 / Sqr(12)
MA(nX, kk(3), 3) = -1 / Sqr(12)
MA(nX, kk(3), 4) = 2 / Sqr(12)
MA(nX, kk(3), 5) = -1 / Sqr(12)
MA(nX, kk(3), 6) = -1 / Sqr(12)
'Row 4
MA(nX, kk(4), 1) = 2 / Sqr(12)
MA(nX, kk(4), 2) = -1 / Sqr(12)
MA(nX, kk(4), 3) = -1 / Sqr(12)
MA(nX, kk(4), 4) = -2 / Sqr(12)
MA(nX, kk(4), 5) = 1 / Sqr(12)
MA(nX, kk(4), 6) = 1 / Sqr(12)
'Row 5
MA(nX, kk(5), 1) = 0
MA(nX, kk(5), 2) = 1 / 2
MA(nX, kk(5), 3) = -1 / 2
MA(nX, kk(5), 4) = 0
MA(nX, kk(5), 5) = -1 / 2
MA(nX, kk(5), 6) = 1 / 2
'Row 6
MA(nX, kk(6), 1) = 0
MA(nX, kk(6), 2) = 1 / 2
MA(nX, kk(6), 3) = -1 / 2
MA(nX, kk(6), 4) = 0
MA(nX, kk(6), 5) = 1 / 2
MA(nX, kk(6), 6) = -1 / 2
以上基矢量，没有满足约化条件的排列。
'Row 1
MA(nX, kk(1), 1) = 1 / Sqr(6)
MA(nX, kk(1), 2) = 1 / Sqr(6)
MA(nX, kk(1), 3) = 1 / Sqr(6)
MA(nX, kk(1), 4) = 1 / Sqr(6)
MA(nX, kk(1), 5) = 1 / Sqr(6)
MA(nX, kk(1), 6) = 1 / Sqr(6)
'Row 2
MA(nX, kk(2), 1) = 1 / Sqr(6)
MA(nX, kk(2), 2) = 1 / Sqr(6)
MA(nX, kk(2), 3) = 1 / Sqr(6)
MA(nX, kk(2), 4) = -1 / Sqr(6)
MA(nX, kk(2), 5) = -1 / Sqr(6)
MA(nX, kk(2), 6) = -1 / Sqr(6)
'Row 3
MA(nX, kk(3), 1) = 2 / Sqr(12)
MA(nX, kk(3), 2) = -1 / Sqr(12)
MA(nX, kk(3), 3) = -1 / Sqr(12)
MA(nX, kk(3), 4) = -2 / Sqr(12)
MA(nX, kk(3), 5) = 1 / Sqr(12)
MA(nX, kk(3), 6) = 1 / Sqr(12)
'Row 4
MA(nX, kk(4), 1) = -2 / Sqr(12)
MA(nX, kk(4), 2) = 1 / Sqr(12)
MA(nX, kk(4), 3) = 1 / Sqr(12)
MA(nX, kk(4), 4) = -2 / Sqr(12)
MA(nX, kk(4), 5) = 1 / Sqr(12)
MA(nX, kk(4), 6) = 1 / Sqr(12)
'Row 5
MA(nX, kk(5), 1) = 0
MA(nX, kk(5), 2) = 1 / 2
MA(nX, kk(5), 3) = -1 / 2
MA(nX, kk(5), 4) = 0
MA(nX, kk(5), 5) = -1 / 2
MA(nX, kk(5), 6) = 1 / 2
'Row 6
MA(nX, kk(6), 1) = 0
MA(nX, kk(6), 2) = 1 / 2
MA(nX, kk(6), 3) = -1 / 2
MA(nX, kk(6), 4) = 0
MA(nX, kk(6), 5) = 1 / 2
MA(nX, kk(6), 6) = -1 / 2
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'Row 1
MA(nX, kk(1), 1) = 1 / Sqr(6)
MA(nX, kk(1), 2) = 1 / Sqr(6)
MA(nX, kk(1), 3) = 1 / Sqr(6)
MA(nX, kk(1), 4) = 1 / Sqr(6)
MA(nX, kk(1), 5) = 1 / Sqr(6)
MA(nX, kk(1), 6) = 1 / Sqr(6)
'Row 2
MA(nX, kk(2), 1) = 1 / Sqr(6)
MA(nX, kk(2), 2) = 1 / Sqr(6)
MA(nX, kk(2), 3) = 1 / Sqr(6)
MA(nX, kk(2), 4) = -1 / Sqr(6)
MA(nX, kk(2), 5) = -1 / Sqr(6)
MA(nX, kk(2), 6) = -1 / Sqr(6)
'Row 3
MA(nX, kk(3), 1) = 2 / Sqr(12)
MA(nX, kk(3), 2) = -1 / Sqr(12)
MA(nX, kk(3), 3) = -1 / Sqr(12)
MA(nX, kk(3), 4) = 2 / Sqr(12)
MA(nX, kk(3), 5) = -1 / Sqr(12)
MA(nX, kk(3), 6) = -1 / Sqr(12)
'Row 4
MA(nX, kk(4), 1) = 0
MA(nX, kk(4), 2) = 1 / 2
MA(nX, kk(4), 3) = -1 / 2
MA(nX, kk(4), 4) = 0
MA(nX, kk(4), 5) = -1 / 2
MA(nX, kk(4), 6) = 1 / 2
'Row 5
MA(nX, kk(5), 1) = 0
MA(nX, kk(5), 2) = -1 / 2
MA(nX, kk(5), 3) = 1 / 2
MA(nX, kk(5), 4) = 0
MA(nX, kk(5), 5) = -1 / 2
MA(nX, kk(5), 6) = 1 / 2
'Row 6
MA(nX, kk(6), 1) = 2 / Sqr(12)
MA(nX, kk(6), 2) = -1 / Sqr(12)
MA(nX, kk(6), 3) = -1 / Sqr(12)
MA(nX, kk(6), 4) = -2 / Sqr(12)
MA(nX, kk(6), 5) = 1 / Sqr(12)
MA(nX, kk(6), 6) = 1 / Sqr(12)
"TC(","nX=",97
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https://blog.sciencenet.cn/blog-2321-38399.html
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