随机温习...
(接前: 27 22 16) “执行定理” 的证明(f++). .
Finally since a(T, X, B) ≥ eps > eps' = a(T, X, B + sL), we have μTν*sL ≥ eps - eps' which implies s ≥ (eps - eps')/q, hence s is bounded from below as required.
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a eps' 25 28 44
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Para 6.1
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(45) 46
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注: 执行定理的 “收官” 之笔.
输入:
---- a: Th1.6的主条件 (X, B) proj. eps-lc.
---- eps': 调用Pro.5.9.之假设.
---- 25: 最大的s, 使得 (X, B + sL) eps'-lc.
---- 28: T, 使得 a(T, X, B + sL) = eps'.
---- 44: μTν*L ≤ q.
输出:
---- 45: μTν*sL ≥ eps - eps'.
---- 46: s ≥ (eps - eps')/q.
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小结: 补上了第六段的逻辑模块.
符号大全、上下标.|| 常用:↑↓ π ΓΔΛΘΩμφΣ∈ ∉ ∪ ∩ ⊆ ⊇ ⊂ ⊃ ≤ ≥ ⌊ ⌋ ⌈ ⌉ ≠ ≡ ⁻⁰ ¹ ² ³ ᵈ ₀ ₁ ₂ ₃ ᵢ .