博文
if语句陷阱
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简单的一个if语句的排列，seq运行截然不同的结果，程序需要逻辑：
程序段1：
fIn=open(fastaFile, 'r')
for line in fIn:
lineNum += 1
if lineNum == 1:
tmp = line.replace('n', '').split('/')
if len(tmp) == 3:
if tmp[2].split('_')[0] == "0":
length = int(tmp[2].split('_')[1])
else:
print "begin coord in seq header is wrong for pacbio fasta file."
return 0
else:
print "seq header format is wrong for pacbio fasta file."
return 0
if line[0] == '>' and lineNum > 1:
print length, len(seq)
if length == len(seq):
return 1
else:
print "end coord in seq header is wrong for pacbio fasta file."
return 0
else:
seq += line.replace('n', '')
fIn.close()
程序段2：
fIn=open(fastaFile, 'r')
for line in fIn:
lineNum += 1
if lineNum == 1:
tmp = line.replace('n', '').split('/')
if len(tmp) == 3:
if tmp[2].split('_')[0] == "0":
length = int(tmp[2].split('_')[1])
else:
print "begin coord in seq header is wrong for pacbio fasta file."
return 0
else:
print "seq header format is wrong for pacbio fasta file."
return 0
if line[0] == '>':
if lineNum > 1:
print length, len(seq)
if length == len(seq):
return 1
else:
print "end coord in seq header is wrong for pacbio fasta file."
return 0
else:
seq += line.replace('n', '')
fIn.close()
https://blog.sciencenet.cn/blog-2890242-1056167.html
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